(I7
I97
I150
(dp0
Vremoval.%l
p1
(Vremoval.cpp
p2
S"#include <iostream>\r\n#define endl '\\n'\r\nusing namespace std;\r\nlong long a[1000000], b[1000000]={2,3,5,7,9,11,13,15,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,101,103,107,109,113,127,131,137,139,149,151,157,163,167,173,179,181,191,193,197,199,211,223,227,229,233,239,241,251,257,263,269,271,277,281,283,293,307,311,313,317,331,337,347,349,353,359,367,373,379,383,389,397,401,409};\r\nint main()\r\n{\r\n    cin.tie(0);\r\n    cout.tie(0);\r\n    short T;\r\n    long long N, q, br, mbr;\r\n    cin >> T;\r\n    for (int i=1; i<=T; i++)\r\n    {\r\n        q=0;\r\n        cin >> N;\r\n        mbr=0;\r\n        for (int j=0; j<N; j++)\r\n        {\r\n            cin >> a[j];\r\n            while (a[j]>b[q])\r\n            {\r\n                q++;\r\n                if (q>80) break;\r\n            }\r\n        }\r\n        for (int k=0;k<q; k++)\r\n        {\r\n           br=0;\r\n           for (int j=0; j<N; j++) if (a[j]%b[k]==0) br++;\r\n           if (mbr<br) mbr=br;\r\n        }\r\n        cout << N-mbr << endl;\r\n    }\r\n    return 0;\r\n}\r\n/**\r\n3\r\n3 2 5 6\r\n6 1 2 3 4 5 6\r\n9 2 2 7 14 56 14 7 13331 1\r\n*/\r\n"
p3
tp4
stp5
.