(I7
I127
I150
(dp0
Vremoval.%l
p1
(Vremoval.cpp
p2
S'#include <bits/stdc++.h>\r\nusing namespace std;\r\nlong long prostidel[5][13],ans[5],x[10001],n[5];\r\nint main(){\r\nios_base::sync_with_stdio(false);\r\ncin.tie(NULL);\r\nlong long maxbr=0;\r\nint t;\r\ncin>>t;\r\nfor(int i=0;i<t;i++){\r\n    cin>>n[i];\r\n    maxbr=0;\r\n\r\n    for(int i1=0;i1<n[i];i1++){\r\n        cin>>x[i1];\r\n        if(x[i1]%2==0){\r\n            prostidel[i][2]++;\r\n            if(prostidel[i][2]>maxbr){\r\n                maxbr=2;\r\n            }\r\n        }\r\n        if(x[i1]%3==0){\r\n            prostidel[i][3]++;\r\n            if(prostidel[i][3]>maxbr){\r\n                maxbr=3;\r\n            }\r\n        }\r\n                if(x[i1]%5==0){\r\n            prostidel[i][5]++;\r\n            if(prostidel[i][5]>maxbr){\r\n                maxbr=5;\r\n            }\r\n        }\r\n                if(x[i1]%7==0){\r\n            prostidel[i][7]++;\r\n            if(prostidel[i][7]>maxbr){\r\n                maxbr=7;\r\n            }\r\n        }\r\n    }\r\n    for(int i1=0;i1<n[i];i1++){\r\n        if(x[i1]%maxbr==0){\r\n            ans[i]++;\r\n        }\r\n    }\r\n\r\n}\r\nfor(int i=0;i<t;i++){\r\n    cout<<n[i]-ans[i]<<endl;\r\n}\r\nreturn 0;\r\n}\r\n'
p3
tp4
stp5
.